A true/false question

Algebra Level 1

If x and y are real numbers, ( x + y ) 2 (x+y)^{2} is always equal to ( x 2 + y 2 ) (x^{2} + y^{2})

True False

Denton Young by Denton Young , 47, USA

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4 solutions

Denton Young
Aug 1, 2015

( x + y ) 2 (x+y)^{2} = x 2 + 2 x y + y 2 x^{2} + 2xy + y^{2}

This only equals x 2 + y 2 x^{2} + y^{2} when x or y = 0. It is equal sometimes, but not always .

5 Helpful 0 Interesting 0 Brilliant 0 Confused
Mohammad Khaza
Jul 28, 2017

x + y ) 2 x+y)^{2} = x 2 + 2 x y + y 2 x^2 +2xy +y^2

so, without 0 this is not possible to eliminate 2 x y 2xy

1 Helpful 0 Interesting 0 Brilliant 0 Confused
Galen Buhain
Feb 27, 2017

(x+y) to the second power is x squared + 2xy + y squared

0 Helpful 0 Interesting 0 Brilliant 0 Confused

(x+y)^2= x^2+2xy+y^2

0 Helpful 0 Interesting 0 Brilliant 0 Confused

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