A Unique Toy

Geometry Level 2

A toy is in the shape of the cylinder a with a hemisphere on one end and a cone on the other.The height and radius of the cylindrical are 13 cm and 5 cm respectively.The radii of the hemispherical and the conical parts are the same as that of the cylindrical part.Calculate the surface area of the toy if height of the conical part is 12 cm.


The answer is 770.

Saurav Sah by Saurav Sah , 20, India

This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try refreshing the page, (b) enabling javascript if it is disabled on your browser and, finally, (c) loading the non-javascript version of this page . We're sorry about the hassle.

3 solutions

s = 1 2 c L + c h + 1 2 ( 4 ) ( π r 2 ) s=\dfrac{1}{2}cL+ch+\dfrac{1}{2}(4)(\pi r^2) where c c is the circumference, L L is the slant height and h h is the height of the cylinder and r r is the radius

s = 1 2 ( 2 π ) ( 5 ) ( 13 ) + 2 π ( 5 ) ( 13 ) + 2 π ( 5 2 ) ≈ 770 s=\dfrac{1}{2}(2\pi)(5)(13) + 2\pi (5)(13) + 2\pi (5^2) \approx \boxed{770}

1 Helpful 0 Interesting 0 Brilliant 0 Confused

Slant height of cone, l=13cm. C.S.A of cone = (pi)rl = 65(pi) C.S.A of cylinder = 2(pi)rh = 130(pi) C.S.A of hemisphere = 2(pi)r^2 = 50(pi) Thus Surface Area of toy = (65+130+50)pi = 245 pi = 245 22/7 = 35 22 = 770 cm^2

1 Helpful 0 Interesting 0 Brilliant 0 Confused

Check it..i got 753.6

Nikita Sheth - 7 years ago
Brahmam Meka
Mar 16, 2015

2 pi r^2 +2 pi r h + pi r s = pi r (2 r +2 h +s ); pi r ( 2*5 + 2 *13 +13 ) =22 *5 /7 (49) ; 110 *7 = 770

0 Helpful 0 Interesting 0 Brilliant 0 Confused

0 pending reports

×

Problem Loading...

Note Loading...

Set Loading...