A variant antiderivative problem

Calculus Level 1

Given that A A is a real number greater than 1, and that 1 A d x x = 2 \displaystyle\int_{1}^{A} \frac {dx}x = 2 .

Find A A to 2 decimal places.


The answer is 7.39.

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2 solutions

Denton Young
Sep 23, 2019

The antiderivative of 1 / x 1/x is l n x ln x

So we need to solve l n A l n 1 = 2 ln A - ln 1 = 2

l n 1 = 0 ln 1 = 0

So l n A = 2 ln A = 2

A = e 2 = 7.39 A = e^2 = 7.39

Got the answer the same way

A Former Brilliant Member - 1 year, 8 months ago
Chew-Seong Cheong
Sep 24, 2019

1 A d x x = 2 ln x 1 A = 2 ln A = 2 A = e 2 7.39 \begin{aligned} \int_1^A \frac {dx}x & = 2 \\ \ln x \ \big|_1^A & = 2 \\ \ln A & = 2 \\ A & = e^2 \approx \boxed{7.39} \end{aligned}

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