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I think at x tends to zero lim of 1/x is doesn't exists .then all doesn't meet the answer I.e doesn't exist. Please correct it .
As we substitute values for x we move closer to zero. 1/2, 1/3, 1/4 etc.
As x approaches infinity, 1/x approaches zero.
Therefore the limit of this is zero.
I have a doubt here As its suggested constant/∞ = 0 so 1/∞ = 0.................(i) And so is 2/∞ = 0....(ii) From equation one and two 1/∞ = 2/∞ which therefore concludes 1 = 2 which is not possible can somebody explain why is it still right to say this 0 ?
Because infinity is not a number, and that's why we can't cancel or compare two infinities.
set ∞ = 9 9 9 9 9
x → ∞ lim x 1 = 9 9 9 9 9 1 = 0 . 0 0 0 0 1 ≈ 0
easy to understand and very helpful for beginners like me -TheGr6inthehouse
Limit means approach.When the numerator is a constant and the denominator get bigger then by the rules of fractions it get smaller.
So x → ∞ lim x 1 = 0
9 1 ≈ 0 . 1 1 1 1 , 9 9 1 ≈ 0 . 0 1 0 1 , 9 9 9 1 ≈ 0 . 0 0 1 , and so on. As the denominator approaches ∞ , x 1 gets closer to 0 .
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The graph of y = x 1 has a horizontal asymptote of y = 0 meaning that as x increases, the value of y tends to 0.
Another solution would be to say that ∞ constant = 0 .