A X B

How many ways are there to select a number from set A and another number from set B such that these two numbers are distinct?

Note: Selecting 3 from A and 4 from B is different from selecting 4 from A and 3 from B.

26 30 28 24

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1 solution

Vaibhav Prasad
Mar 27, 2015

There are 6 6 ways of choosing a number from A. There are 5 5 ways of choosing a number from B. Thus the total number of arranges is 6 × 5 = 30 6 \times 5 = 30 .

The number of ways in which we can select the same number from both the sets is 4 4 , i.e, 3 3 , 4 4 , 5 5 , 6 6 3-3, 4-4, 5-5, 6-6 .

Hence 30 4 = 26 30-4 = 26

Nice sol n ^{n} bro!

Harsh Shrivastava - 6 years, 2 months ago

Yay! In this case, it's much easier to take everything, and then remove the ones that you don't want.

Chung Kevin - 6 years, 2 months ago

Beautiful procedure, i just counted the number !

Mahtab Hossain - 6 years, 2 months ago

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