a n = 100 + n 2 a_n = 100+n^2

The numbers in the sequence 101 , 104 , 109 , 116 , . . . 101, 104, 109,116, . . . are of the form a n = 100 + n 2 a_n = 100+n^2 , where n = 1 , 2 , 3 , . . . . n = 1, 2, 3, . . . . For each n n , let d n d_n be the greatest common divisor of a n a_n and a n + 1 a_{n+1} .

Find the maximum value of d n d_n as n n ranges through the positive integers.


The answer is 401.

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