Triangle A B C ABC has A B = 10 AB=10 and A C = 14 AC=14 . A point P P is randomly chosen in the interior or on the boundary of triangle A B C ABC . What is the probability that P P is closer to A B AB than to A C AC ?

5 12 \frac{5}{12} 1 4 \frac{1}{4} 5 7 \frac{5}{7} 2 3 \frac{2}{3} 3 7 \frac{3}{7} 1 3 \frac{1}{3} 3 4 \frac{3}{4}

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