ABC=CBA

Algebra Level 2

Given that A = 2 5 / 8 , B = 3 1 / 3 a n d C = 4 1 / 4 t h e n A={ 2 }^{ { 5 }/{ 8 } },\quad B={ 3 }^{ { 1 }/{ 3 } }\quad and\quad C={ 4 }^{ { 1 }/{ 4 } }\quad then

All of the are equal men!! C>B>A A>B>C A>C>B

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1 solution

Compare A and B.Raise A and B to the power of 24 you get 2 15 2^{15} and 3 8 = 6561 3^8=6561 . 2 12 = 4096 , 2 13 = 8192 > 6561 2^{12}=4096,2^{13}=8192>6561 So 2 15 > 3 8 A > B 2^{15}>3^8\rightarrow A> B . C = 4 1 4 = 2 1 2 C=4^{\frac{1}{4}}=2^{\frac{1}{2}} which is less than A and B.So the answer is A > B > C \boxed{A> B> C}

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