About Riemann-Zeta function (2). Inspired by and dedicated to Sambhrant Sachan

Calculus Level 4

k = 2 ζ ( k ) \large \displaystyle \sum_{k = 2}^\infty \zeta (k)

What is the behaviour of the sum above?

Notation: ζ ( ) \zeta (\cdot) denotes the Riemann-zeta function. .


Try Part I

Can't be determined Undecidable in ZFC It converges It diverges

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1 solution

Two proofs:

1. \boxed{1.-} ζ ( k ) > 1 , ( k 2 , k N ) k = 2 ζ ( k ) = + \large \displaystyle \zeta (k) > 1, \space (\forall k \ge 2, \space k \in \mathbb{N}) \Rightarrow \sum_{k =2}^\infty \zeta(k) = + \infty

2. \boxed{2.-}

If k = 2 ζ ( k ) \displaystyle \sum_{k = 2}^\infty \zeta(k) converged then lim k ζ ( k ) = 0 \displaystyle \lim_{k\to \infty} \zeta(k) = 0 , but lim k ζ ( k ) = 1 \displaystyle \lim_{k\to \infty} \zeta(k) = 1 , so the previous sum doesn't converge and therefore, due to 1 \boxed{1} it diverges to + +\infty

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