ABSCISSA

Calculus Level pending

What is the abscissa of the point on y = x^2 – x where the tangent is horizontal?


The answer is 0.5.

Psalm Lemuel Guevarra by Psalm Lemuel Guevarra , 27, Philippines

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2 solutions

Wendel Maquidato
Mar 26, 2015

Y=x^2-x derivative Y'=2x-1 ;y'=0 (maximum) 2x-1=0 X=0.5

1 Helpful 0 Interesting 0 Brilliant 0 Confused

A horizontal line has a slope equal to 0.

Hence, y’ = 0 at that point.

Then, y = x^2 – x 

 y’ = 2x – 1 but y’ = 0

0 = 2x – 1

x = ½
0 Helpful 0 Interesting 0 Brilliant 0 Confused

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