Absolutely, Norm!

If $z = a + bi$ , then the norm is given by:

$N(z) = a^2 + b^2$

And the absolute value is given by:

$|z| = \sqrt{a^2 + b^2} = \sqrt{N(z)} = \sqrt{100} = \boxed{10}$

The norm of a Gaussian integer is defined as the square of the absolute value. Therefore, the absolute value of a Gaussian integer is the square root of the absolute value. Therefore, if the norm of a Gaussian integer is 100, the absolute value is the square root of 100, which is 10.