Suppose and are two groups . from to be an onto homomorphism . If contains an element of order 8 , does that imply has an element of order ? Give reason for your answer
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Let b be the element in G ′ whose order is 8. As it is an epimorphism we know that there exist a in G such that ϕ ( a ) = b .We know that order of ϕ ( a ) divides o ( a ) .
Now as evident the order of the a has to be a multiple of 8 . So let order of a = 8 k where k is some positive integer. Now as order of a divides order of G . Order of G has to be of the form 8 k m . Where m is some other positive integer. Now order of a k would be 8 . Hence there exist an element of order 8 in G