A.C. isn't always cool!

An AC circuit is given below:

The source voltage is given by V = V o s i n ( ω t ) V=V_o sin (\omega t) where ω \omega is the angular frequency, t t is time and V o V_o is the peak voltage. At t = 0 t=0 current drawn from the source is 0 A 0 A and it begins to flow in the direction as shown. Assume that the diodes do not allow any current to flow through them in the reverse biased condition. At t = 7 π 6 ω t= \frac{7\pi}{6\omega} , current flows through:

The diode which was forward biased at 0 < t < π ω 0<t< \frac{\pi}{\omega} The diode which was reverse biased at 0 < t < π ω 0<t< \frac{\pi}{\omega} None of the diodes Both the diodes

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1 solution

Maharnab Mitra
Jan 25, 2014

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I uploaded the images in the solution but they are not showing now. Please visit link 1 and link 2 .

Thank you.

Maharnab Mitra - 7 years, 4 months ago

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