Accelerating car

Classical Mechanics Level 1

The above picture depicts a car, which was moving on a straight line with a velocity of 20 20 m/s, is now speeding up for 2 2 seconds, raising the velocity up to 40 40 m/s. If the rate of change of the velocity of the car is constant, then what are the acceleration and the moving distance during the 2 2 seconds, respectively?

− 10 m/s 2 -10 \text{ m/s}^2 , 60 60 m − 20 m/s 2 -20 \text{ m/s}^2 , 160 160 m 10 m/s 2 10 \text{ m/s}^2 , 60 60 m 20 m/s 2 20 \text{ m/s}^2 , 160 160 m

Lakshan Dumpa by Lakshan Dumpa , 24, India

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2 solutions

Muhamed Higazy
May 3, 2014

acc.=[v(in.)+v(fi.)]/2 ...... (40-20)/2=10m/s^2 ....... S=V(in.) t+1/2 a t^2 ....... 20 2+1/2 10 4=60m

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Rishabh Singh
Apr 22, 2014

just put the values in eq. s=u.t+1/2a.t^2 a=v-u/t-0

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