Accelerating in electric field

Electricity and Magnetism Level 2

A point charge is in uniformly accelerated motion (in the $+x$ direction) in a uniform electric field. After being put at point A , it passes through points B and C , as shown above. Let $v_B$ and $v_C$ denote the speeds of the point charge at points B and C , respectively. Then what is the ratio $v_B:v_C?$

2:5

1:\sqrt{3}

\sqrt{2}:\sqrt{5}

1:3

2 solutions

A Former Brilliant Member
May 12, 2014

As the motion of charged particle is uniformly accelerating we can use the formula-V^2=U^2+2as and here u=0.Ratio of s1 and s2 is 1:3, therefore ratio of velocities is 1:1.73.

Arghyanil Dey
Apr 15, 2014

Let, the distance between two iso electric lines is D

So the electric field in the region is 1/D

Magnitude of force on the charge is Q/D [where Q is the charge of the particle]

If the mass of the particle is m, the acceleration of the particle is Q/Dm

Let, X&Y is the velocities of the particle at point B&C respectively .

Then X^2=2×Q/Dm×D ,Y^2=2×Q/Dm×3D

Then X/Y=1/√3.

Accelerating in electric field

2 solutions

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