acceleration
Classical Mechanics
Level
2
Give (v-t) relationof a moving particle.
V^2=2t^2+14
Find the magnitude of acceleration after 1 second of motion. Give answer in decimal. No unit required.
The answer is 0.5.
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1 solution
So, V=(2t^2+14)^(1/2) dv/dt=2t/V (Cause,V is a function of t)
putting t=1 we get
dv/dt=1/2=.5 therefore the acceleration must be .5 unit/time^2