Acceleration

Calculus Level 3

Velocity of a car as a function of time is given by v x = A + B t 2 v_{x} = A+Bt^{2} , where A = 3.00 A=3.00 and B = 0.10 B=0.10 of appropriate SI units. Find the average acceleration for the time interval t = 0 t=0 to t = 5 s t=5s .

1.25 ms − 2 1.25\text{ ms}^{-2} 0.5 ms − 2 0.5\text{ ms}^{-2} 1 ms − 2 1\text{ ms}^{-2} 0.75 ms − 2 0.75\text{ ms}^{-2}

Sparsh Sarode by Sparsh Sarode , 22, India

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1 solution

Sparsh Sarode
May 14, 2016

v x = A + B t 2 v_x=A+Bt^{2}

Here t 1 = 0 s t_1=0s and t 2 = 5 s t_2=5s

v 1 = 3 + ( 0.1 ) ( 0 ) 2 = 3 m s − 1 v_1=3+(0.1)(0)^{2}=3ms^{-1}

v 2 = 3 + ( 0.1 ) ( 5 ) 2 = 5.5 m s − 1 v_2=3+(0.1)(5)^{2}=5.5ms^{-1}

Average acceleration= 5.5 − 3 5 − 0 = 0.5 m s − 1 \frac{5.5-3}{5-0}=0.5ms^{-1}

3 Helpful 0 Interesting 1 Brilliant 0 Confused

nice solution Sarode...

Ramiel To-ong - 4 years ago

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