Acceleration Due to Earth's Gravity

The apparent value of $g$ includes a "centrifugal component", accounting for the fact that, due to inertia, objects on earth tend to travel in a straight line rather than following the earth's curvature. This centrifugal component makes everything appear approximately 0.1% lighter than it really is. Its magnitude is $\Delta g_{cp} = -\omega^2r,$ where $\omega$ is the angular frequency of the earth's rotation and $r = R\sin\lambda$ the radius of the circle on which a point of earth is rotating. ( $\lambda$ is the latitude of your location on earth). The radius of this circle is greatest for points on the equator $\lambda = 0$ and zero on the poles $\lambda = \pm 90^\circ$ .

Stopping the rotation of the earth would take away this centrifugal component, $\Delta g_{cp}$ , thereby generally increasing the apparent value of $g$ . However, " at some other places ", that is, on the north and south poles, $\Delta g_{cp} = 0$ , so that stopping the earth's rotation has no effect; only here it remains the same .

Increase at equators and remain same at poles. Pretty simple!