Acceleration due to Gravity
What decimal of
g
, which is the acceleration due to gravity, would the inward acceleration of a reasonably high-speed train at 75 meters per second be traveling around a track with radius of curvature 3 kilometers? Give the whole number and the first 3 decimals as your final answer.
The answer is 1.875.
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1 solution
a ~ (v^2)/r
a ~ ((75 m/s)^2))/3000 m
a ~ 1.875 m/s^{2}