Acceleration in elliptical orbits

A planet P P is orbiting a star S S in an elliptical path. At the instant shown in the diagram, find the direction of the net acceleration of the planet.

Towards the center C C Towards the star S S Tangential to the path Perpendicular to velocity, in plane of the orbit

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2 solutions

Since the distance from the center of the orbit is non-uniform because it is an ellipse rather than a circular orbit, there is a tangential acceleration as well as a centripetal acceleration because the velocity is non-zero. The magnitude of the acceleration can be given by the Pythagorean Theorem, using the square root of the sums of the squares of both the centripetal and tangential accelerations. Drawing a vector diagram of this resulting vector will show that dir(a) points towards S.

Odinrawo201 Rom
Apr 7, 2017

The star is what provides the pull on the planet, gravity. Say gravity is G then it makes sense that G would be strongest closest to its source.

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