AC/DC not the band. 2

The AC power source would be a sine wave with a RMS voltage measured at 120 Volts. The diode on the left would allow only the negative voltage phase of the AC cycle to the capacitor on the left. The diode on the right would allow only the positive voltage phase of the AC cycle to the capacitor on the right. The capacitors would be charged to the peak of the AC – and peak AC + voltages.

${ { V }_{ peak } }=\quad { V }_{ RMS }\quad \sqrt { 2 } \quad =\quad 120\quad \sqrt { 2 } \quad =\quad 169.7V$

${ { V }_{ total } }=\quad { 2\quad \bullet \quad V }_{ peak }\quad =\quad 2\quad \bullet \quad 169.7V\quad =\quad 339.4\quad volts$