In the acutangle triangle ABC, the heights BE and CF intersect and H, with E on the AC side and F on the AB side. Suppose that the circuncenter of ABC belongs to segment EF. Demonstrate that HA² = HB² + HC²
This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try
refreshing the page, (b) enabling javascript if it is disabled on your browser and,
finally, (c)
loading the
non-javascript version of this page
. We're sorry about the hassle.
No explanations have been posted yet. Check back later!