ADAM LEVINE

Algebra Level 1

Suppose Adam Levine had 3 wives, 6 dogs, 9 houses. Each wife has the same amount of possessions. How many dogs and houses do each own?

2houses and 3 dogs 2dogs and 3houses 10 houses and 3dogs 3dogs and 4 houses

Michelle Wang by Michelle Wang , 20, China

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1 solution

Alex Delhumeau
Jun 3, 2015

6 dogs 3 wives & 9 houses 3 wives = 2 dogs and 3 houses per wife \large{\frac{6\text{ dogs}}{3\text{ wives}} \text{ \& } \frac{9 \text{ houses}}{3 \text{ wives}}=\boxed{2 \text{ dogs and } 3 \text { houses per wife}}} .

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