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The formula for the sum of n terms of this series (which , by the way , is the triangle numbers) will be a quadratic polynomial, so let a n 2 + b n + c = S n . Then, 9 a + 3 b + c = 6 , 4 a + 2 b + c = 3 and a + b + c = 1 . Solving this system of equations gives a = 2 1 , b = 2 1 and c = 0 . Therefore , we have S n = 2 n 2 + n . Plugging in 1 0 into this gives 2 1 0 2 + 1 0 = 2 1 1 0 = 5 5 . Thank you for watching...