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find the sum of all even numbers from 1-100


The answer is 2550.

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6 solutions

Damiann Mangan
Mar 14, 2014

2 + 4 + 6 + + 100 = 2 ( 1 + 2 + 3 + + 50 ) = 2 50 51 2 = 50 51 = 2550 2+4+6+\dots+100=2(1+2+3+\dots+50)=2*\frac{50*51}{2}=50*51=2550

Rahma Anggraeni
May 19, 2014

n = 50 n=50

a = 2 a=2

b = 2 b=2

S n = n 2 ( 2 a + ( n 1 ) b ) S_{n}=\frac{n}{2}(2a+(n-1)b)

S 50 = 50 2 ( 2 × 2 + ( 50 1 ) 2 ) S_{50}=\frac{50}{2}(2 \times 2+(50-1)2)

S 50 = 25 ( 4 + 98 ) S_{50}=25(4+98)

S 50 = 2550 S_{50}=\boxed{2550}

Amritesh Anand
Apr 19, 2014

n(n+1)/4=2550

Jo E
Apr 3, 2014

This is a sum of an arithmetic series.

= n(A1 + An) 2 = 50(2+100)/2 =50 (102)/2 =50*51 =2550

Sunil Pradhan
Mar 23, 2014

sum of even numbers from 1 to n = n(n+1) = 50 × 51 = 2550

sum of odd numbers from 1 to n = n²= 50² = 2500

Hassam Rind
Mar 14, 2014

the even number are paired number or the counting of 2 like 2,4,6,8,10....... so the sum of even numbers upto 100 is 2+4+6+8+10+..............................+100=2550

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