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n = 5 0
a = 2
b = 2
S n = 2 n ( 2 a + ( n − 1 ) b )
S 5 0 = 2 5 0 ( 2 × 2 + ( 5 0 − 1 ) 2 )
S 5 0 = 2 5 ( 4 + 9 8 )
S 5 0 = 2 5 5 0
This is a sum of an arithmetic series.
= n(A1 + An) 2 = 50(2+100)/2 =50 (102)/2 =50*51 =2550
sum of even numbers from 1 to n = n(n+1) = 50 × 51 = 2550
sum of odd numbers from 1 to n = n²= 50² = 2500
the even number are paired number or the counting of 2 like 2,4,6,8,10....... so the sum of even numbers upto 100 is 2+4+6+8+10+..............................+100=2550
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2 + 4 + 6 + ⋯ + 1 0 0 = 2 ( 1 + 2 + 3 + ⋯ + 5 0 ) = 2 ∗ 2 5 0 ∗ 5 1 = 5 0 ∗ 5 1 = 2 5 5 0