Addition of vectors

6 * (2, -1, 0) - 4 * ( -4, 2, 5) + 2 * (0, 0, 3) = (12, -6, 0) + (16, -8, -20) + (0, 0, 6) = (28, -14, -14)

the answer is 28, -14, -14 !!!!!!! Hey I am hritik kaushik from radhika appts! flat no.73

6 * (2, -1, 0) - 4 * ( -4, 2, 5) + 2 * (0, 0, 3) = (12, -6, 0) + (16, -8, -20) + (0, 0, 6) = (28, -14, -14)

During addition of vectors the components get added. So add them accordingly after multiplying

We have to take one value for each variable at a time.

$a=(2,-1,0), b=(-4,2,5), c=(0,0,3)$

So, the first value of $6a-4b+2c$ is:

$6a-4b+2c=6\times2-4\times(-4)+2\times0$

$6a-4b+2c=12+16+0$

$6a-4b+2c=28$

Second value of $6a-4b+2c$ is:

$6a-4b+2c=6\times(-1)-4\times2+2\times0$

$6a-4b+2c=-6-8+0$

$6a-4b+2c=-14$

Third value of $6a-4b+2c$ is:

$6a-4b+2c=6\times0-4\times5+2\times3$

$6a-4b+2c=0-20+6$

$6a-4b+2c=-14$

Thus, the answer is: $6a-4b+2c=\boxed{(28,-14,-14)}$