Addition Problem

Just simple logic!

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At the top, $3$ Soft Drinks = $30$ so each Soft Drink must be $10$ as $30\div3=10$ .

$x~ +~ x~ +~ x~ =~ 30$ then $30~ \div ~ 3~ =~ 10$ so 1 soft drink = 10 .

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We already know that $1$ Soft Drink equals $10$ so we find what $20 - 10$ is, which, by all means, equals to $10$ . Next we have $2$ Hamburgers that cost $10$ in total so we repeat the process we did to the first part; so $10\div 2=5$ so now we know that $1$ Hamburger equals $5$ .

$10~ +~ x~ +~ x~ =~ 20$ then $20~-~10~=~10$ then $10~ \div ~ 2~ =~ 5$ so 1 Hamburger = 5 .

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Next we look at the last problem, $1$ Hamburger + $2$ Fries = $9$ . Since we know how much a hamburger costs 5, we solve $9~-~5~=4$ . There are 2 Fries so we do $4~\div ~2~=~2$ . So this means 1 Fries equals 2.

$5~+~x~+~x~=~9$ then $9~-~5~=~4$ then $4~\div~2~=~2$ so 1 Fries = 2 .

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Finally we have all our numbers! The question is asking what is Hamburger + Fries + Soft Drink so we do $10~+~5~+~2~=~17$ .

So our final answer is $\boxed{17}$

I think the question is "How much is Hamburger + Fries + Soft drink = ?"

Hint

Add up how much the Hamburger cost, Fries, and Soft drink