Aditya Ranjan

it is very simple... just divide the two non-edge attached boxes ex. 18/2 =9 so 54/6 =9 their quotients are equal, then do it with the second boxes of numbers 81/9 =9 so 27/x = should be 9 by solving x we get x=27/9 x= 3

thank me later !!!

Numbers in the second square are 3/2 times the numbers in first square.

We can see in 1st box..........6/2=3 is multiplied by 18 is equal to 54 similarly......(9/x)*27=81 Therefore by solving x=3

In the first box you can see going clockwise, two is multiplied by 3 up to 54. Using the same logic, as 9 times 3 = 27 and 27 times 3 = 81, we can divide 9 by 3 to get the answer, which is 3.

9 in the right table is multiplied with left table elements and the product i.e. 54 & 18 had written cross to each other therefore what should be multiplied with 9 in right table to get 81 & 27 which is 3.