Advanced Math Test #Geometry_3

Level pending

Given a circle with its center (O) and a constant diameter AB. A point M is placed on the circumference of the circle such that M isn't overlapping A or B. C is symmetric to O through A. The line, which is perpendicular to AB at C, meets AM at N. BN meets the circumference of the circle at a second point E. BM meets CN at F.

What should point A be in order that NF has the minimum length?

None of the other answers is correct. A is the centroid of triangle BNF A is the circumcenter of triangle BNF A is the incenter of triangle BNF A is the orthocenter of triangle BNF A can be any points in triangle BNF.

Tin Le by Tin Le , 15, Vietnam

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