Again:))

Level pending

$f(x)\times (x+1) = (x+2)\times f(x+3)$ and

$f(13) = 15^{2}\times 16\times 18^{2}\times 19...53^{2}\times 54$

As for that, what is the $\textit{f(55)}$ ?

\frac{54!}{14!}

\frac{53!}{14!}

\frac{53!}{13!}

\frac{54!}{13!}

0 solutions

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