Age
Two time’s the father’s age is more than times his sons age. Ten year’s ago, the sum of their ages was . What is the present age of the son?
The answer is 15.
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1 solution
F = father’s present age
s = son’s present age
at present: 2 F = 8 + 6 s ( 1 )
10 years ago: F − 1 0 + s − 1 0 = 4 4 ⟹ F = 6 4 − s ( 2 )
Substitute ( 2 ) in ( 1 ) , we have
2 ( 6 4 − s ) = 8 + 6 s
1 2 8 − 2 s = 8 + 6 s
1 2 0 = 8 s
1 5 = s