Age does matters!

Algebra Level 2

The average age of 10 members of a committee is the same as it was 4 years ago, because an old member has been replaced by a young member.

Find how much younger is the new member than old one ?


The answer is 40.

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1 solution

Let the sum of nine member (total) =x and the age of old one=z so its average 4 yrs before= x + z 10 . \frac{x+z}{10}. after 4 yrs let z be replaced by y. so now avg= ( x + 4 10 + y ) 10 \frac {(x+4*10+y)}{10}

now x + z 10 = x + 40 + y 10 \frac{x+z}{10} = \frac {x+40+y}{10} so after solving it found z=y+40.

so old person is 40yrs older than young one.

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