Age gap
Algebra
Level
1
A man is six times as old as his son. If the difference of their ages is 35, what is the sum of their ages?
The answer is 49.
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1 solution
m = present age of the man
s = present age of the man's son
The first equation is: m = 6s amd the second equation is m – s = 35.
Solving the system of equations gives m = 42 and s = 7. So the desired answer is: 42 + 7 = 49.