Ah! There goes a ship!

A ship moving at a constant acceleration of 36 km h r 2 hr^{-2} in a fixed direction speeds up from 12 km/h to 18 km/h. Find the distance traveled by the ship during this time.


The answer is 2.5.

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2 solutions

Vishal S
Dec 29, 2014

We know that 2as=v^2-u^2

From this s=v^2-u^2 / 2a

=>s=18^2-12^2 / 72

=>s=180/72

=>s=2.5

Abishek Nathan
Dec 26, 2014

Use v^2 - u^2=2as.
v=18km/hr , u=12km/hr , a=36km/hr^2 , s=(18^2 -12^2 )/ (2×36) = 2.5 km.

Yeah! the third equation of motion will come handy in this problem!! Good work.

Just a small suggestion. Please edit this solution and mention clearly what you mean by v, u, a and s

Mehul Arora - 6 years, 5 months ago

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Mention the units you used in the answer. One might answer it in meters

Pranjal Jain - 6 years, 5 months ago

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Thanks! I will surely mention the units!!

Mehul Arora - 6 years, 5 months ago

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