AIEEE Problems.

Classical Mechanics Level 2

A marble block of mass 2 kg lying on ice when given a velocity of 6 m/s is stopped by friction in 10 seconds.Then what is the coefficient of friction?


The answer is 0.06.

Anandhu Raj by Anandhu Raj , 23, India

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1 solution

Jaswinder Singh
Aug 7, 2014

V = u + at where v=0 u =6 Therefore a = -0.6.. Force on block is the frictional force... .....ma= coefficient of friction × mg.....

0 Helpful 0 Interesting 0 Brilliant 0 Confused

coeficient of friction=ma/mg.which is equal to a/g=0.6/9.8=0.06

Hari Kanhangad - 6 years, 10 months ago

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