Determine the number of non-negative integers that satisfy the equation
(Note: if is any real number, then denotes the largest integer less than or equal to .)
This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try
refreshing the page, (b) enabling javascript if it is disabled on your browser and,
finally, (c)
loading the
non-javascript version of this page
. We're sorry about the hassle.
Let a = ⌊ 4 4 x ⌋ = ⌊ 4 5 x ⌋
4 4 values of x 0 ≤ x ≤ 4 3 , a = 0
4 3 values of x 4 5 ≤ x ≤ 8 7 , a = 1
4 2 values of x 9 0 ≤ x ≤ 1 3 1 , a = 2
.
.
.
2 values of x 1 8 9 0 ≤ x ≤ 1 8 9 1 , a = 4 2
1 value of x 1 9 3 5 ≤ x ≤ 1 9 3 5 , a = 4 3
So the number of non-negative values of x = 2 4 4 × 4 5 = 9 9 0 .