AIMO 2015 Q9

A sequence is formed by the following rules:

s 1 = a , s 2 = b s_1 = a, s_2 = b and s n + 2 = s n + 1 + ( 1 ) n s n s_{n+2} = s_{n+1} + (-1)^n s_n for all n 1 n \geq 1 .

If a = 3 a=3 and b < 1000 b < 1000 , what is the largest integral value of b b for which 2015 is a member of the sequence?


The answer is 253.

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1 solution

Anand Raj
Jun 12, 2019

If the second term is b b , then after writing a few terms of the series, I found that the terms were of the form: b b , b 3 b-3 , 2 b 3 2b-3 , 3 b 3 3b-3 , 5 b 6 5b-6 , 8 b 9 8b-9 and so on. Equating these values to 2015 gives the first integer answer for 8 b 9 = 2015 b = 253 8b-9=2015\Rightarrow b=253 .

FunFact: This sequence follows a Fibonacci pattern except for its second term, b 3 b-3 .

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