Airplane

A 6000 kg 6000\text{ kg} airplane is flying in a straight line at a constant speed. The force of air friction is 3000 N 3000\text{ N} .

What is the net force on the plane?

0 N 2 N 19.6 N 3000 N

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1 solution

Tom Engelsman
Oct 3, 2017

We require F n e t = F t h r u s t F a i r = m d v d t F_{net} = F_{thrust} - F_{air} = m \cdot \frac{dv}{dt} , where v ( t ) v(t) is the velocity as a function of time. Since the plane's speed is constant (i.e. v ( t ) = C v(t) = C ), the acceleration is zero ( d v d t = 0 \frac{dv}{dt} = 0 ). Thus F t h r u s t = F a i r = 3000 N F n e t = 0 N . F_{thrust} = F_{air} = 3000N \Rightarrow F_{net} = \boxed{0N}.

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