Algebra 4

Algebra Level 1

3 8 − 1 5 = ? \frac38 - \frac15 = \, ?

7 40 \frac7{40} 6 40 \frac6{40} 5 40 \frac5{40} 8 40 \frac8{40}

Charlotte Milanese by Charlotte Milanese , 17, USA

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4 solutions

we can only add and subtract proper fractions if they have equal denominators, if the denominators are unequal we need to find the LCM. in this problem the LCM is 80.

3 8 − 1 5 = \frac{3}{8}-\frac{1}{5}= 5 ( 3 ) − 8 ( 1 ) 40 = \frac{5(3)-8(1)}{40}= 15 − 8 40 = \frac{15-8}{40}= 7 40 \frac{7}{40}

2 Helpful 0 Interesting 0 Brilliant 0 Confused

yep you got it ! :)

Charlotte Milanese - 4 years, 5 months ago
Mohammad Khaza
Jul 23, 2017

3 8 \frac{3}{8} - 1 5 \frac{1}{5}

= 15 − 8 40 \frac{15-8}{40}

= 7 40 \frac{7}{40}

1 Helpful 0 Interesting 0 Brilliant 0 Confused

3/8 - 1/5 = 15/40 - 8/40 = 7/40

1 Helpful 0 Interesting 0 Brilliant 0 Confused
Mahdi Raza
Jun 7, 2020

\[\begin{align} &= \dfrac{(5)3}{(5)8} - \dfrac{(8)1}{(8)5} \\ \\ &= \dfrac{15 - 8}{5 \times 8} \\ \\ &= \boxed{\dfrac{7}{40}}

\end{align}\]

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