Algebra

Algebra Level 1

20142014 × 20142014 20142013 × 20142015 = ? 20142014\times20142014-20142013\times20142015 = \ ?

5 4 1 2 0

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1 solution

Kay Xspre
Sep 11, 2015

This question is not hard. Define ζ = 20142014 \zeta = 20142014 then ζ 1 = 20142013 \zeta-1 = 20142013 and ζ + 1 = 20142015 \zeta+1 = 20142015 . Substitution gives ζ 2 ( ζ 1 ) ( ζ + 1 ) \zeta^{2}-(\zeta-1)(\zeta+1) = ζ 2 ( ζ 2 1 ) = 1 \zeta^2-(\zeta^2-1) = 1

i like it very good

Addanki Raghavendra - 5 years, 9 months ago

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