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1 solution
Let the point having angle x be Q. Take the center O and join A, C and X with it. It's gud to find that OC is perpendicular to CQ. In ∆AOC base angles will be 5° each. Then in ∆ACQ it is easy to find angle CAQ or angle CAX. We have angle COX =2 × angleCAX... Thus we get angle COX =120°. I don't know how to post a pic with a solution, it wud have been easy with the pic..!!