ALGEBRA

too lame

f(2)=6(2)+1=13 and f(1)=6(1)=1=7 SO F(2)-f(1)=13-7=6

f(2) 6(2)+1=13 f(1) 6(1)+1=7 f(2)-f(1)=13-7 sol=6

$f(2) - f(1) = 13 - 7 = \color{#69047E}{\boxed{6}}$ .

The slope of the expression is the coefficient of $x$ , which is $6$ . Thus the instantaneous change between any two points that are one away from each other (such as $1$ and $2$ ) have a change in the $y$ -axis of $\boxed{6}$ .

f(2) - f(1) = [6(2)+1]- [6(1)+1] = 13-7 = 6

13-7=6

in the function subsituting the values of 2 and 1 in separate equations ,we get, f(2) = 2X6 +1 that is 13 , similarly f(1) = 1X6 +1 =7 Subtracting f(2) - f(1) we get 13 -7 =6 ANS

K.K.GARG,INDIA