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1 solution
y =c( c y + b z) + a z =>(1-c^2)y= (b c + a)z........(1)
z =b( c y + b z ) + a y =>(1-b^2)z= (b c + a)y........(2)
from (1) & (2) =>1- c^2/ b c + a = b c + a /1 - b ^2
=>1- b^2 - c^2 + b^2 c^2 = b^2 c^2 + a b c + a b c + a^2
=>a^2 + b^2 + c^2 - 1 = -2abc (ans)