Algebra in age too

Algebra Level 2

The age of the father is 40 years more than that of his son.After 5 years,father’s age will be thrice his son’s age. Find their present ages.

father’s age is 60 and son’s age is 15 father’s age is 60 and son’s age is 20 father’s age is 65 and son’s age is 25 father’s age is 60 and son’s age is 10 father’s age is 55 and son’s age is 15 father’s age is 50 and son’s age is 10

2 solutions

Mahdi Raza
May 18, 2020

Son's age $= x \implies$ Father's age $= 40+x$ . After 5 years:

$3(x+5) = (40+x+5)$

$3x + 15 = 45 + x$

$2x = 30$

$x = \boxed{15} \implies 40+x = \boxed{55}$

A Former Brilliant Member
Oct 6, 2017

Let $f$ and $s$ be the present ages of the father and son, respectively. Then

$f=40+s$ $\color{#D61F06}(1)$

$f+5=3(s+5)$ $\color{#D61F06}(2)$

Substitute $\color{#D61F06}(1)$ in $\color{#D61F06}(2)$ , we have

$40+s+5=3s+15$

$40+5-15=3s+5$

$s=15$

It follows that,

$f=40+15=55$

Algebra in age too

2 solutions

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