Algebra of Function

Algebra Level 3

If we have f ( x ) + x f ( 1 x ) = x x 1 f(x)+xf(1-x)=\frac{x}{x-1} and f ( 2 ) = a b , f(2)=\frac{a}{b}, then determine a 2 + b 2 + b a a^2+b^2+\frac{b}{a} .


The answer is 13.

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2 solutions

Damiann Mangan
Mar 11, 2014

By assigning x x as 2 2 , we get

f ( 2 ) + 2 f ( 1 ) = 2 f(2)+2f(-1)=2

while assigning x x as 1 -1 , we would have

f ( 1 ) f ( 2 ) = 1 2 f(-1)-f(2)=\frac{1}{2}

2 f ( 1 ) 2 f ( 2 ) = 1 \leftrightarrow 2f(-1)-2f(2)=1 .

By subtracting first to second equation, we get f ( 2 ) = 1 3 f(2)=\frac{1}{3} which would reveal the a a , b b , and the solution, 13 13 .

Vandana Verma
Mar 24, 2014

Put x=2 and x=-1 in given equation then we have two values of f(-1); 1.f(-1)=1-(a/2b) ; x=2 and 2.f(-1)=0.5+(a/b); x=-1. Then after solving this we have a:b=1:3=f(2). So, for this value ans is 13

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