Algebra on the floor
Level
2
If [x] denotes the maximum integer less than or equal to x, find the sum of all solutions of equation .
The answer is 6.
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1 solution
( 4 × 2 . 7 5 ) − ( 2 × ⌊ 2 . 7 5 ⌋ ) = 1 1 − 4 = 7
( 4 × 3 . 2 5 ) − ( 2 × ⌊ 3 . 2 5 ⌋ ) = 1 3 − 6 = 7
2 . 7 5 + 3 . 2 5 = 6