Which is larger:
A = 9 0 % 9 0 %
B = 9 0 % × 9 0 %
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A = 9 0 % 9 0 % , so now take a chocolate break it into say something 5 parts and take 5 parts so now what will you say we have taken whole chocolate, so A = 9 0 % 9 0 % = 1, B = 1 0 0 9 0 * 1 0 0 9 0 (Note: I am not gonna simplify first 90% and another 90% this will be okay but I am doing straight forward multiply first then simplify) so B = 1 0 , 0 0 0 8 1 0 0 so now simplify it so B = 1 0 0 8 1 so know how is greater B = 1 0 0 8 1 or A = 1 = 1 0 0 1 0 0 so A is greater than B. 😊😊😊👌🏻
This problem will become much easier if you first write the percentages as decimals. In this case, the equations can be rewritten as A = . 9 . 9 B = . 9 × . 9 Any non-zero number divided by itself returns a value of 1, so A = 1 . Also, any number multiplied by a value < 1 reduces the value of the number, so B < 1 . Therefore, your answer should be A .
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9 0 % = 0 . 9
Now,
A.
⇒ 0 . 9 0 . 9 = 1
B.
⇒ 0 . 9 × 0 . 9 = 0 . 8 1
So, A = 1 and B = 0 . 8 1
Therefore A > B or 1 > 0 . 8 1