Algebra Skills

Algebra Level 3

If 2 m 2m is the average of 2 k 2k and 3 d 3d , what is the average of 4 m − 2 k 4m-2k for d = 2 d=2 ?


The answer is 3.

Atta-Owusu Theophilus by Atta-Owusu Theophilus , 23, Ghana

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1 solution

The average of 2k and 3d is simply (2k+3d)÷2 which equals 2m. Cross multiply giving 4m=2k+3d. So then, if d=2, we have 4m=2k+6. Making 2k the subject gives 4m-6. Again finding the average means dividing both sides of your result by 2, giving 2m-k=3. Which is our required solution to the problem. Convinced?

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