Algebraic Electronics!

It is obvious that $Z_{1}, Z_{2}, ... Z_{2015}$ are zeroes of the polynomial $y = (x-2)^{2015} - 2^{2017}$ . Thus, by Vieta's formulas, we can get the net impedance of network Q, which is the quotient of the constant over the coefficient in $x$ (Do you see why?). That is, $\frac { 2^{2015}+ 2^{2017} }{2015\cdot2^{2014}}$ , which simplifies to $\frac{2}{403}$ ohms. Since there are $2015$ of these in series, we finally get the answer $2015 \cdot\frac{2}{403}=\boxed{10}$ .