All are correct, right?

Chemistry Level 3

C H X 3 C O O N H X 4 + H X 2 O → ? \large\ce{CH_3COONH_4 + H_2O -> } \, ?

What products would the above reaction fetch?

The given reaction is impossible to happen C H X 3 C O O H + N H X 4 ( a q ) X + \ce{CH_3COOH + NH_{4(aq)}^{+}} All the given products are correct C H X 3 C O O X − X ( a q ) + N H X 4 ( a q ) X + \ce{CH_3COO^{-}_{(aq)} + NH_{4(aq)}^{+}} C H X 3 C O O X − X ( a q ) + N H X 4 O H \ce{CH_3COO^{-}_{(aq)} + NH_4OH} C H X 3 C O O H + N H X 4 O H \ce{ CH_3COOH + NH_4OH}

Nihar Mahajan by Nihar Mahajan , 20, India

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1 solution

Ashish Menon
May 27, 2016

All the products are not correct because they are different.

When C H X 3 C O O N H X 4 \ce{CH_3COONH_4} dissolves in water it breaks up into C H 3 C O O X − \ce{{CH_3COO}^{-}} (acetate ion) and N H 4 X + \ce{{NH_4}^{+}} (ammonium ion). Water molecule itself breaks up into H X + \ce{{H}^{+}} (hydrogen ion) and OH X − \ce{{OH}^{-}} (hydroxyl ion). Now, for the reaction to be possible acetate ion combines with hydrogen ion. Similarly, the ammonium ion combines with hydroxyl ion forming C H X 3 C O O H \ce{CH_3COOH} (acetic acid) and N H X 4 O H \ce{NH_4OH} (ammonium hydroxide). Since they want to get their octet complete, they do not form ions as three of the option states.

And the option "reaction is not possible" is only to confuse.

So, the answer is C H X 3 C O O H + N H X 4 O H \color{#69047E}{\boxed{\ce{CH_3COOH + NH_4OH}}} .

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